A = 10 B = 23 n. intervals = 14
median = 17 media / mean = 16.73846153846154
%: | 0.77 | 0 | 0 | 0.77 | 9.23 | 10 | 22.31 | 24.62 | 20 | 9.23 | 1.54 | 0 | 0 | 1.54 |
• Supponiamo di disporre di una sequenza di dati non classificati, come le seguenti misure in mm delle lunghezze di una certa quantità di fave, misurate da degli alunni di 12 anni. Le misure sono espresse con numeri interi. Basta inserire i dati senza introdurre altri input.
• Suppose we have a sequence of unclassified data, such as the following measurements (in mm) of the lengths of a certain number of beans, measured by 12-year-old pupils. Measurements are expressed in integers. Just enter the data without introducing other inputs.
14, 17, 18, 14, 17, 18, 14, 17, 19, 14, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 23, 16, 17, 16, 17, 16, 17, 16, 17, 16, 18, 16, 18, 16, 18, 16, 18, 16, 18, 16, 18, 10, 16, 17, 18, 13, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 19, 15, 16, 17, 19, 15, 16, 18, 19, 15, 16, 18, 19, 15, 17, 18, 19, 16, 17, 18, 20, 16, 17, 18, 20, 16, 17, 18, 23, 14, 17, 18, 14, 17, 18, 14, 17, 19, 14, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 19, 15, 17, 23, 16, 17, 16, 17, 16, 17, 16, 17, 16, 18, 16, 18, 16, 18, 16, 18, 16, 18, 16, 18, 10, 16, 17, 18, 13, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 14, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 19, 15, 16, 17, 19, 15, 16, 18, 19, 15, 16, 18, 19, 15, 17, 18, 19, 16, 17, 18, 20, 16, 17, 18, 20, 16, 17, 18, 23
Alternativa, con gli stessi esiti / Alternative, with the same results
10*2, 13*2, 14*24, 15*26, 16*58, 17*64, 18*52, 19*24, 20*4, 23*4