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f'(x)=f(x), f(1)=4
y'(x)=(1+x^2)/x^2, y(-2)=0

s"(t)=5, s'(0)=1, s(0)=2
s"(t)=5, s'(0)=1, s(0)=2, s(1) = ?

S'(t) = 0.01 − S(t)/100,   S(0) = 5

dy/dx = x-y, y(-1) = 3
dy/dx = x-y, y(1) = -1
dy/dx = x-y, y(2) = -2
plot -1 + 5*e^(-1-x) + x, -1 - e^(-1-x) + x, -1 - 3*e^(2-x) + x, -2 < x < 5
slope field of dy/dx = x-y, for -2 < x < 5, -2 < y < 5

y'(x) = 1+x/(y(x)^2+1)
slope field of dy/dx = 1+x/(y^2+1), for -8 < x < 4, -4 < y < 4

s"(t) + 3*s'(t) − t = 5
y"(x) = -4*y(x), y(0)=2, y'(0)=0
y"(x) = -4*y(x)+cos(2*x), y(0)=2, y'(0)=0	
y"(x) = -4*y(x)-y'(x), y(0)=1, y'(0)=3

d/dy f(x,y) = x

d^2/dy^2 f(x,y) = x
d/dx d/dy f(x,y) = 0

d^2/dt^2( f(x,t) ) = k^2*(d^2/dx^2( f(x,t) ) )

3*(d/dx f(x,y)) + 2*(d/dy f(x,y)) = 0
plot f(x,y) = sin(y-2*x/3) for -4 < x < 4, -4 < y < 4

 ALTRO